Given the aggression scores below for Outcome A of the sleep deprivation experiment, verify that, as suggested earlier, these mean differences shouldn’t be taken seriously by testing the null hypothesis at the .05 level of significance. Use the computation formulas for the various sums of squares and summarize results with an ANOVA table.

HOURS OF SLEEP DEPRIVATION

ZERO: 3, 5, 7

TWENTY-FOUR: 4, 8, 6

FORTY-EIGHT: 2, 4, 6

Group mean: 5, 6, 4. Grand mean = 5

18.2

A recent example of interaction from the psychological literature is the tendency of college students, when assigning prison sentences on the basis of photos of “convicted defendants,” to judge attractive swindlers more harshly than unattractive swindlers but to judge attractive robbers less harshly than unattractive robbers.

Construct a data (or line) graph showing this interaction. As is customary, identify the vertical axis with the dependent variable, the mean prison sentence assigned by students. For the sake of uniformity, identify the two points along the horizontal axis with swindlers and robbers, and identify the two lines inside the graph with attractive and unattractive defendants.
Assume that, in fact, there is no interaction. Instead, independently of their degree of attractiveness, swindlers are judged more harshly than robbers, and, independently of their crime, unattractive defendants are judged more harshly than attractive defendants. Using the same identifications as in the previous question, construct data graph that depicts this result.